Thread: So, no overloading [][]?

I have a 1D array that is treated as a 2D (long story). Is there a way to get calls like array[i][j] work? operator[][] (int x, int y) gives me a syntax error...

If it is indeed a 1d array then id have to say it cant be called using [][] what would the second be pointing to? Can you give us a better example of what your trying to do? Why you want a 1d array to be treated as a 2d array?

Well, you can overload () for it and by that way treat it as 2D. And as I said, it's a long story...

Foundations:

You have a class. This class should be indexable by double index ( [i][j] ). As a single operator, as you have experienced, it isn't possible. However, if you think it's worth the time, you can do the following:

Create a function that does what you need as a normal member function "Indexer( int x, int y )".

Create a single indexer ( [] ), that returns another object of a user defined class. This class defines another indexer that returns the parents class' Indexer function.

Example:

PHP Code:

#include <stdio.h>

class UsesDoubleIndexer
{
    public:
    class dblidx
    {
        private:
            int m_x;
            UsesDoubleIndexer* m_Parent;
        public:
            dblidx( int x, UsesDoubleIndexer* Parent )
            {
                m_x = x;
                m_Parent = Parent;
            }
            
            int operator [] ( int y )
            {
                return m_Parent.Indexer( m_x, y );
            }
    }

    dblidx operator [] ( int x )
    {
        return dblidx( x, this );
    }

    int Indexer( int x, int y )
    {
        // your indexer function here
        return 2*x+y;
    }
};

int main()
{
    UsesDoubleIndexer udi;

    printf("%d", udi[0][3] );

    return 0;
} 


I've no compiler handy... so this is just an educated guess